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100m^2-36=0
a = 100; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·100·(-36)
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120}{2*100}=\frac{-120}{200} =-3/5 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120}{2*100}=\frac{120}{200} =3/5 $
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